Y = log_1_0(Q)
Q = 10^Y
P(Q \le q) = P(10^Y \le q) = P[Y \le log_1_0(q)] = F_Y[log_1_0(q)]
\frac{\delta}{\delta x} F_Y[log_1_0(q)] = f_Y[log_1_0(q)]\frac{1}{qln(10)}
Therefore, the PDF of discharge Q is computed as:
f_Q(q) = \frac{f_Y[log_1_0(q)]}{qln(10)}
where f_Y is the PDF of the normal distribution